Base | Representation |
---|---|
bin | 11001111111010101010001… |
… | …101011111111001101011010 |
3 | 112222201021212221210212121101 |
4 | 121333111101223333031122 |
5 | 104440221212243242132 |
6 | 1043034121030302014 |
7 | 33035100125601235 |
oct | 3177252153771532 |
9 | 488637787725541 |
10 | 114303335134042 |
11 | 3346985488a68a |
12 | 109a09037b790a |
13 | 4ba19b1b5c892 |
14 | 203244d30641c |
15 | d3345aa6e7e7 |
hex | 67f551aff35a |
114303335134042 has 4 divisors (see below), whose sum is σ = 171455002701066. Its totient is φ = 57151667567020.
The previous prime is 114303335134013. The next prime is 114303335134061. The reversal of 114303335134042 is 240431533303411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 114292114181001 + 11220953041 = 10690749^2 + 105929^2 .
It is a junction number, because it is equal to n+sod(n) for n = 114303335133992 and 114303335134010.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28575833783509 + ... + 28575833783512.
Almost surely, 2114303335134042 is an apocalyptic number.
114303335134042 is a deficient number, since it is larger than the sum of its proper divisors (57151667567024).
114303335134042 is an equidigital number, since it uses as much as digits as its factorization.
114303335134042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57151667567023.
The product of its (nonzero) digits is 155520, while the sum is 37.
Adding to 114303335134042 its reverse (240431533303411), we get a palindrome (354734868437453).
The spelling of 114303335134042 in words is "one hundred fourteen trillion, three hundred three billion, three hundred thirty-five million, one hundred thirty-four thousand, forty-two".
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