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11430443133 = 3211279112603
BaseRepresentation
bin10101010010100111…
…01011100001111101
31002111121101200012200
422221103223201331
5141402143140013
65130122022113
7553154110044
oct125123534175
932447350180
1011430443133
11493620711a
122270047939
131102167825
147a611b55b
1546d767e73
hex2a94eb87d

11430443133 has 12 divisors (see below), whose sum is σ = 16512250560. Its totient is φ = 7619552136.

The previous prime is 11430443113. The next prime is 11430443201. The reversal of 11430443133 is 33134403411.

It is not a de Polignac number, because 11430443133 - 212 = 11430439037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11430443097 and 11430443106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11430443113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 45210 + ... + 157812.

It is an arithmetic number, because the mean of its divisors is an integer number (1376020880).

Almost surely, 211430443133 is an apocalyptic number.

It is an amenable number.

11430443133 is a deficient number, since it is larger than the sum of its proper divisors (5081807427).

11430443133 is a wasteful number, since it uses less digits than its factorization.

11430443133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123888 (or 123885 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 11430443133 its reverse (33134403411), we get a palindrome (44564846544).

The spelling of 11430443133 in words is "eleven billion, four hundred thirty million, four hundred forty-three thousand, one hundred thirty-three".

Divisors: 1 3 9 11279 33837 101511 112603 337809 1013427 1270049237 3810147711 11430443133