1143113003423 has 4 divisors (see below), whose sum is σ = 1151336838120. Its totient is φ = 1134889168728.

The previous prime is 1143113003419. The next prime is 1143113003519. The reversal of 1143113003423 is 3243003113411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1143113003423 - 2² = 1143113003419 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1143113003392 and 1143113003401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1143113000423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4111917140 + ... + 4111917417.

It is an arithmetic number, because the mean of its divisors is an integer number (287834209530).

Almost surely, 2^{1143113003423} is an apocalyptic number.

1143113003423 is a deficient number, since it is larger than the sum of its proper divisors (8223834697).

1143113003423 is an equidigital number, since it uses as much as digits as its factorization.

1143113003423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8223834696.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1143113003423 its reverse (3243003113411), we get a palindrome (4386116116834).

The spelling of 1143113003423 in words is "one trillion, one hundred forty-three billion, one hundred thirteen million, three thousand, four hundred twenty-three".