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114313533003143 = 177431644270353
BaseRepresentation
bin11001111111011110110001…
…100001110001010110000111
3112222202021012122220022002222
4121333132301201301112013
5104440403103422100033
61043042525002122555
733035610625214105
oct3177366141612607
9488667178808088
10114313533003143
1133473108261681
12109a288aab045b
134ba2948839456
142032b39854c75
15d33855eb5598
hex67f7b1871587

114313533003143 has 4 divisors (see below), whose sum is σ = 114314177450928. Its totient is φ = 114312888555360.

The previous prime is 114313533003139. The next prime is 114313533003157. The reversal of 114313533003143 is 341300335313411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114313533003143 - 22 = 114313533003139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114313533002143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321957746 + ... + 322312607.

It is an arithmetic number, because the mean of its divisors is an integer number (28578544362732).

Almost surely, 2114313533003143 is an apocalyptic number.

114313533003143 is a deficient number, since it is larger than the sum of its proper divisors (644447785).

114313533003143 is an equidigital number, since it uses as much as digits as its factorization.

114313533003143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 644447784.

The product of its (nonzero) digits is 58320, while the sum is 35.

Adding to 114313533003143 its reverse (341300335313411), we get a palindrome (455613868316554).

The spelling of 114313533003143 in words is "one hundred fourteen trillion, three hundred thirteen billion, five hundred thirty-three million, three thousand, one hundred forty-three".

Divisors: 1 177431 644270353 114313533003143