Base | Representation |
---|---|
bin | 11001111111011111010011… |
… | …100011111111011100000111 |
3 | 112222202022200110100110221201 |
4 | 121333133103203333130013 |
5 | 104440410241111314003 |
6 | 1043043101400523331 |
7 | 33035631030541435 |
oct | 3177372343773407 |
9 | 488668613313851 |
10 | 114314104010503 |
11 | 33473380607991 |
12 | 109a2a0a180547 |
13 | 4ba2a09c23727 |
14 | 2032b91611d55 |
15 | d3388b1a7b1d |
hex | 67f7d38ff707 |
114314104010503 has 16 divisors (see below), whose sum is σ = 115557360730560. Its totient is φ = 113074997607936.
The previous prime is 114314104010453. The next prime is 114314104010537. The reversal of 114314104010503 is 305010401413411.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114314104010503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114314104016503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 299345401 + ... + 299727037.
It is an arithmetic number, because the mean of its divisors is an integer number (7222335045660).
Almost surely, 2114314104010503 is an apocalyptic number.
114314104010503 is a deficient number, since it is larger than the sum of its proper divisors (1243256720057).
114314104010503 is a wasteful number, since it uses less digits than its factorization.
114314104010503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 387066.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 114314104010503 its reverse (305010401413411), we get a palindrome (419324505423914).
The spelling of 114314104010503 in words is "one hundred fourteen trillion, three hundred fourteen billion, one hundred four million, ten thousand, five hundred three".
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