Base | Representation |
---|---|
bin | 11001111111100000001111… |
… | …101001111011111110101011 |
3 | 112222202102021201102220220021 |
4 | 121333200033221323332223 |
5 | 104440414322210432110 |
6 | 1043043345413541311 |
7 | 33035665022200624 |
oct | 3177401751737653 |
9 | 488672251386807 |
10 | 114315112202155 |
11 | 33473848716227 |
12 | 109a304b944837 |
13 | 4ba2b3aa6b337 |
14 | 2032c49492a4b |
15 | d338e99562da |
hex | 67f80fa7bfab |
114315112202155 has 16 divisors (see below), whose sum is σ = 144443288505600. Its totient is φ = 86611670655840.
The previous prime is 114315112202131. The next prime is 114315112202209. The reversal of 114315112202155 is 551202211513411.
It is not a de Polignac number, because 114315112202155 - 29 = 114315112201643 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 114315112202155.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 188245425 + ... + 188851714.
It is an arithmetic number, because the mean of its divisors is an integer number (9027705531600).
Almost surely, 2114315112202155 is an apocalyptic number.
114315112202155 is a deficient number, since it is larger than the sum of its proper divisors (30128176303445).
114315112202155 is a wasteful number, since it uses less digits than its factorization.
114315112202155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 377100354.
The product of its (nonzero) digits is 12000, while the sum is 34.
Adding to 114315112202155 its reverse (551202211513411), we get a palindrome (665517323715566).
The spelling of 114315112202155 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred twelve million, two hundred two thousand, one hundred fifty-five".
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