Base | Representation |
---|---|
bin | 11001111111100100111011… |
… | …010101100000111001010111 |
3 | 112222202220021010011011222001 |
4 | 121333210323111200321113 |
5 | 104441010121320410033 |
6 | 1043045540341220131 |
7 | 33036233432655661 |
oct | 3177447325407127 |
9 | 488686233134861 |
10 | 114320140013143 |
11 | 33475998799019 |
12 | 109a4013701647 |
13 | 4ba345c5b671c |
14 | 20331a5113531 |
15 | d33ae1052e7d |
hex | 67f93b560e57 |
114320140013143 has 4 divisors (see below), whose sum is σ = 114324116256288. Its totient is φ = 114316163770000.
The previous prime is 114320140013129. The next prime is 114320140013173. The reversal of 114320140013143 is 341310041023411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114320140013143 - 25 = 114320140013111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114320140013173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1988078446 + ... + 1988135947.
It is an arithmetic number, because the mean of its divisors is an integer number (28581029064072).
Almost surely, 2114320140013143 is an apocalyptic number.
114320140013143 is a deficient number, since it is larger than the sum of its proper divisors (3976243145).
114320140013143 is an equidigital number, since it uses as much as digits as its factorization.
114320140013143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3976243144.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 114320140013143 its reverse (341310041023411), we get a palindrome (455630181036554).
The spelling of 114320140013143 in words is "one hundred fourteen trillion, three hundred twenty billion, one hundred forty million, thirteen thousand, one hundred forty-three".
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