1143221130313 has 4 divisors (see below), whose sum is σ = 1150792131328. Its totient is φ = 1135650129300.

The previous prime is 1143221130301. The next prime is 1143221130367. The reversal of 1143221130313 is 3130311223411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1143221130313 - 2⁵ = 1143221130281 is a prime.

It is a super-3 number, since 3×1143221130313³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1143221130013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3785500281 + ... + 3785500582.

It is an arithmetic number, because the mean of its divisors is an integer number (287698032832).

Almost surely, 2^{1143221130313} is an apocalyptic number.

It is an amenable number.

1143221130313 is a deficient number, since it is larger than the sum of its proper divisors (7571001015).

1143221130313 is an equidigital number, since it uses as much as digits as its factorization.

1143221130313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7571001014.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1143221130313 its reverse (3130311223411), we get a palindrome (4273532353724).

The spelling of 1143221130313 in words is "one trillion, one hundred forty-three billion, two hundred twenty-one million, one hundred thirty thousand, three hundred thirteen".