11433040334041 has 6 divisors (see below), whose sum is σ = 11813745112026. Its totient is φ = 11064232580400.

The previous prime is 11433040334017. The next prime is 11433040334059. The reversal of 11433040334041 is 14043304033411.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 6569379086400 + 4863661247641 = 2563080^2 + 2205371^2 .

It is not a de Polignac number, because 11433040334041 - 2¹³ = 11433040325849 is a prime.

It is a super-2 number, since 2×11433040334041² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11433040333994 and 11433040334012.

It is not an unprimeable number, because it can be changed into a prime (11433040334081) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5948511180 + ... + 5948513101.

It is an arithmetic number, because the mean of its divisors is an integer number (1968957518671).

Almost surely, 2^{11433040334041} is an apocalyptic number.

It is an amenable number.

11433040334041 is a deficient number, since it is larger than the sum of its proper divisors (380704777985).

11433040334041 is an equidigital number, since it uses as much as digits as its factorization.

11433040334041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11897024343 (or 11897024312 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 11433040334041 its reverse (14043304033411), we get a palindrome (25476344367452).

The spelling of 11433040334041 in words is "eleven trillion, four hundred thirty-three billion, forty million, three hundred thirty-four thousand, forty-one".