Base | Representation |
---|---|
bin | 10101010010111011… |
… | …00101101000111001 |
3 | 1002111210021122001021 |
4 | 22221131211220321 |
5 | 141403324243231 |
6 | 5130253422441 |
7 | 553215145264 |
oct | 125135455071 |
9 | 32453248037 |
10 | 11433040441 |
11 | 4937720559 |
12 | 2270a9aa21 |
13 | 1102866ab4 |
14 | 7a65d5cdb |
15 | 46dacc811 |
hex | 2a9765a39 |
11433040441 has 4 divisors (see below), whose sum is σ = 11742041572. Its totient is φ = 11124039312.
The previous prime is 11433040393. The next prime is 11433040453. The reversal of 11433040441 is 14404033411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14404033411 = 17 ⋅847296083.
It can be written as a sum of positive squares in 2 ways, for example, as 6782346025 + 4650694416 = 82355^2 + 68196^2 .
It is a cyclic number.
It is not a de Polignac number, because 11433040441 - 221 = 11430943289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11433041441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154500510 + ... + 154500583.
It is an arithmetic number, because the mean of its divisors is an integer number (2935510393).
Almost surely, 211433040441 is an apocalyptic number.
It is an amenable number.
11433040441 is a deficient number, since it is larger than the sum of its proper divisors (309001131).
11433040441 is an equidigital number, since it uses as much as digits as its factorization.
11433040441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 309001130.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 11433040441 its reverse (14404033411), we get a palindrome (25837073852).
The spelling of 11433040441 in words is "eleven billion, four hundred thirty-three million, forty thousand, four hundred forty-one".
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