Base | Representation |
---|---|
bin | 10000101000110010110… |
… | …001000000110101111011 |
3 | 11001022002110010122121220 |
4 | 100220302301000311323 |
5 | 122213001112310133 |
6 | 2233121501403123 |
7 | 145413235144521 |
oct | 20506261006573 |
9 | 4038073118556 |
10 | 1143313010043 |
11 | 40097042a566 |
12 | 1656b92694a3 |
13 | 83a773467b9 |
14 | 3d49da7a311 |
15 | 1eb1825a5b3 |
hex | 10a32c40d7b |
1143313010043 has 4 divisors (see below), whose sum is σ = 1524417346728. Its totient is φ = 762208673360.
The previous prime is 1143313010029. The next prime is 1143313010083. The reversal of 1143313010043 is 3400103133411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1143313010043 - 210 = 1143313009019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1143313009995 and 1143313010022.
It is not an unprimeable number, because it can be changed into a prime (1143313010023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190552168338 + ... + 190552168343.
It is an arithmetic number, because the mean of its divisors is an integer number (381104336682).
Almost surely, 21143313010043 is an apocalyptic number.
1143313010043 is a deficient number, since it is larger than the sum of its proper divisors (381104336685).
1143313010043 is an equidigital number, since it uses as much as digits as its factorization.
1143313010043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 381104336684.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1143313010043 its reverse (3400103133411), we get a palindrome (4543416143454).
The spelling of 1143313010043 in words is "one trillion, one hundred forty-three billion, three hundred thirteen million, ten thousand, forty-three".
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