11433202103 has 4 divisors (see below), whose sum is σ = 11699090568. Its totient is φ = 11167313640.

The previous prime is 11433202073. The next prime is 11433202147. The reversal of 11433202103 is 30120233411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30120233411 = 557 ⋅54075823.

It is a cyclic number.

It is not a de Polignac number, because 11433202103 - 2¹⁴ = 11433185719 is a prime.

It is a super-2 number, since 2×11433202103² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11433202153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132944168 + ... + 132944253.

It is an arithmetic number, because the mean of its divisors is an integer number (2924772642).

Almost surely, 2^11433202103 is an apocalyptic number.

11433202103 is a deficient number, since it is larger than the sum of its proper divisors (265888465).

11433202103 is an equidigital number, since it uses as much as digits as its factorization.

11433202103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 265888464.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 11433202103 its reverse (30120233411), we get a palindrome (41553435514).

The spelling of 11433202103 in words is "eleven billion, four hundred thirty-three million, two hundred two thousand, one hundred three".