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1143332443135 = 51481315436879
BaseRepresentation
bin10000101000110011111…
…011001001001111111111
311001022010210200221211001
4100220303323021033333
5122213021101140020
62233123434111131
7145413562263001
oct20506373111777
94038123627731
101143332443135
114009803a2973
1216570387b4a7
1383a7b38bb7c
143d4a2498371
151eb19ce850a
hex10a33ec93ff

1143332443135 has 8 divisors (see below), whose sum is σ = 1372091641920. Its totient is φ = 914604147744.

The previous prime is 1143332443007. The next prime is 1143332443139. The reversal of 1143332443135 is 5313442333411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1143332443135 - 27 = 1143332443007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1143332443094 and 1143332443103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1143332443139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7644375 + ... + 7792504.

It is an arithmetic number, because the mean of its divisors is an integer number (171511455240).

Almost surely, 21143332443135 is an apocalyptic number.

1143332443135 is a deficient number, since it is larger than the sum of its proper divisors (228759198785).

1143332443135 is a wasteful number, since it uses less digits than its factorization.

1143332443135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15451697.

The product of its digits is 155520, while the sum is 37.

Adding to 1143332443135 its reverse (5313442333411), we get a palindrome (6456774776546).

The spelling of 1143332443135 in words is "one trillion, one hundred forty-three billion, three hundred thirty-two million, four hundred forty-three thousand, one hundred thirty-five".

Divisors: 1 5 14813 74065 15436879 77184395 228666488627 1143332443135