Base | Representation |
---|---|
bin | 11001111111110111110100… |
… | …001011110000110101100111 |
3 | 112222211211121112121201011211 |
4 | 121333313310023300311213 |
5 | 104441323140301024033 |
6 | 1043103133031412251 |
7 | 33040552140315403 |
oct | 3177676413606547 |
9 | 488754545551154 |
10 | 114340421111143 |
11 | 33483555961137 |
12 | 109a7b33824087 |
13 | 4ba53422a1726 |
14 | 203416a88c103 |
15 | d343cb7e72cd |
hex | 67fdf42f0d67 |
114340421111143 has 4 divisors (see below), whose sum is σ = 114344193134368. Its totient is φ = 114336649087920.
The previous prime is 114340421111123. The next prime is 114340421111149. The reversal of 114340421111143 is 341111124043411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114340421111143 - 29 = 114340421110631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114340421111149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885966143 + ... + 1886026768.
It is an arithmetic number, because the mean of its divisors is an integer number (28586048283592).
Almost surely, 2114340421111143 is an apocalyptic number.
114340421111143 is a deficient number, since it is larger than the sum of its proper divisors (3772023225).
114340421111143 is an equidigital number, since it uses as much as digits as its factorization.
114340421111143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3772023224.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 114340421111143 its reverse (341111124043411), we get a palindrome (455451545154554).
The spelling of 114340421111143 in words is "one hundred fourteen trillion, three hundred forty billion, four hundred twenty-one million, one hundred eleven thousand, one hundred forty-three".
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