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11434121323 = 25934409611
BaseRepresentation
bin10101010011000011…
…01101100001101011
31002111212022112201221
422221201231201223
5141404113340243
65130332522511
7553230266452
oct125141554153
932455275657
1011434121323
114938299649
122271320437
131102b54a81
147a67d7b99
1546dc42bed
hex2a986d86b

11434121323 has 4 divisors (see below), whose sum is σ = 11438533528. Its totient is φ = 11429709120.

The previous prime is 11434121311. The next prime is 11434121381. The reversal of 11434121323 is 32312143411.

11434121323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11434121323 - 25 = 11434121291 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11434125323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2202213 + ... + 2207398.

It is an arithmetic number, because the mean of its divisors is an integer number (2859633382).

Almost surely, 211434121323 is an apocalyptic number.

11434121323 is a deficient number, since it is larger than the sum of its proper divisors (4412205).

11434121323 is an equidigital number, since it uses as much as digits as its factorization.

11434121323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4412204.

The product of its digits is 1728, while the sum is 25.

Adding to 11434121323 its reverse (32312143411), we get a palindrome (43746264734).

The spelling of 11434121323 in words is "eleven billion, four hundred thirty-four million, one hundred twenty-one thousand, three hundred twenty-three".

Divisors: 1 2593 4409611 11434121323