Base | Representation |
---|---|
bin | 1101101000010… |
… | …11010111010101 |
3 | 21222011010211012 |
4 | 12310023113111 |
5 | 213232410313 |
6 | 15202422005 |
7 | 2555612441 |
oct | 664132725 |
9 | 258133735 |
10 | 114341333 |
11 | 595a7377 |
12 | 32361905 |
13 | 1a8c53c2 |
14 | 11285821 |
15 | a088da8 |
hex | 6d0b5d5 |
114341333 has 4 divisors (see below), whose sum is σ = 117130188. Its totient is φ = 111552480.
The previous prime is 114341323. The next prime is 114341341. The reversal of 114341333 is 333143411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 58644964 + 55696369 = 7658^2 + 7463^2 .
It is a cyclic number.
It is not a de Polignac number, because 114341333 - 24 = 114341317 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114341299 and 114341308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114341323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1394366 + ... + 1394447.
It is an arithmetic number, because the mean of its divisors is an integer number (29282547).
Almost surely, 2114341333 is an apocalyptic number.
It is an amenable number.
114341333 is a deficient number, since it is larger than the sum of its proper divisors (2788855).
114341333 is an equidigital number, since it uses as much as digits as its factorization.
114341333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2788854.
The product of its digits is 1296, while the sum is 23.
The square root of 114341333 is about 10693.0506872454. The cubic root of 114341333 is about 485.3642114938.
Adding to 114341333 its reverse (333143411), we get a palindrome (447484744).
The spelling of 114341333 in words is "one hundred fourteen million, three hundred forty-one thousand, three hundred thirty-three".
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