Base | Representation |
---|---|
bin | 10101010011000101… |
… | …11001111100011111 |
3 | 1002111212220110002222 |
4 | 22221202321330133 |
5 | 141404203344320 |
6 | 5130343335555 |
7 | 553233042152 |
oct | 125142717437 |
9 | 32455813088 |
10 | 11434434335 |
11 | 4938492835 |
12 | 22714515bb |
13 | 1102c3439c |
14 | 7a6879c99 |
15 | 46dca5825 |
hex | 2a98b9f1f |
11434434335 has 4 divisors (see below), whose sum is σ = 13721321208. Its totient is φ = 9147547464.
The previous prime is 11434434313. The next prime is 11434434373. The reversal of 11434434335 is 53343443411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11434434335 - 212 = 11434430239 is a prime.
It is a super-2 number, since 2×114344343352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11434434295 and 11434434304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1143443429 + ... + 1143443438.
It is an arithmetic number, because the mean of its divisors is an integer number (3430330302).
Almost surely, 211434434335 is an apocalyptic number.
11434434335 is a deficient number, since it is larger than the sum of its proper divisors (2286886873).
11434434335 is an equidigital number, since it uses as much as digits as its factorization.
11434434335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2286886872.
The product of its digits is 103680, while the sum is 35.
Adding to 11434434335 its reverse (53343443411), we get a palindrome (64777877746).
The spelling of 11434434335 in words is "eleven billion, four hundred thirty-four million, four hundred thirty-four thousand, three hundred thirty-five".
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