11435490613 has 4 divisors (see below), whose sum is σ = 12037358560. Its totient is φ = 10833622668.

The previous prime is 11435490607. The next prime is 11435490629. The reversal of 11435490613 is 31609453411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31609453411 = 58771 ⋅537841.

It is a cyclic number.

It is not a de Polignac number, because 11435490613 - 2¹⁷ = 11435359541 is a prime.

It is a super-2 number, since 2×11435490613² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11435490683) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300933945 + ... + 300933982.

It is an arithmetic number, because the mean of its divisors is an integer number (3009339640).

Almost surely, 2^11435490613 is an apocalyptic number.

It is an amenable number.

11435490613 is a deficient number, since it is larger than the sum of its proper divisors (601867947).

11435490613 is an equidigital number, since it uses as much as digits as its factorization.

11435490613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601867946.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 11435490613 in words is "eleven billion, four hundred thirty-five million, four hundred ninety thousand, six hundred thirteen".