114400000120213 has 4 divisors (see below), whose sum is σ = 118090322704768. Its totient is φ = 110709677535660.

The previous prime is 114400000120201. The next prime is 114400000120229. The reversal of 114400000120213 is 312021000004411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114400000120213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114400000120313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1845161292231 + ... + 1845161292292.

It is an arithmetic number, because the mean of its divisors is an integer number (29522580676192).

Almost surely, 2^{114400000120213} is an apocalyptic number.

It is an amenable number.

114400000120213 is a deficient number, since it is larger than the sum of its proper divisors (3690322584555).

114400000120213 is an equidigital number, since it uses as much as digits as its factorization.

114400000120213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3690322584554.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 114400000120213 its reverse (312021000004411), we get a palindrome (426421000124624).

The spelling of 114400000120213 in words is "one hundred fourteen trillion, four hundred billion, one hundred twenty thousand, two hundred thirteen".