11440124213 has 4 divisors (see below), whose sum is σ = 13074427680. Its totient is φ = 9805820748.

The previous prime is 11440124207. The next prime is 11440124231. The reversal of 11440124213 is 31242104411.

11440124213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31242104411 = 7 ⋅4463157773.

It is a cyclic number.

It is not a de Polignac number, because 11440124213 - 2⁶ = 11440124149 is a prime.

It is a super-3 number, since 3×11440124213³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11440124203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 817151723 + ... + 817151736.

It is an arithmetic number, because the mean of its divisors is an integer number (3268606920).

Almost surely, 2^11440124213 is an apocalyptic number.

It is an amenable number.

11440124213 is a deficient number, since it is larger than the sum of its proper divisors (1634303467).

11440124213 is an equidigital number, since it uses as much as digits as its factorization.

11440124213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1634303466.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 11440124213 its reverse (31242104411), we get a palindrome (42682228624).

The spelling of 11440124213 in words is "eleven billion, four hundred forty million, one hundred twenty-four thousand, two hundred thirteen".