Base | Representation |
---|---|
bin | 10000101001011100111… |
… | …111011011101100110111 |
3 | 11001100220211011021102111 |
4 | 100221130333123230313 |
5 | 122220423441330033 |
6 | 2233320045351451 |
7 | 145436626510141 |
oct | 20513477335467 |
9 | 4040824137374 |
10 | 1144021433143 |
11 | 4011a43022a6 |
12 | 165876568587 |
13 | 83b5b044a74 |
14 | 3d529ba7c91 |
15 | 1eb5a5437cd |
hex | 10a5cfdbb37 |
1144021433143 has 4 divisors (see below), whose sum is σ = 1144027210960. Its totient is φ = 1144015655328.
The previous prime is 1144021433129. The next prime is 1144021433207. The reversal of 1144021433143 is 3413341204411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1144021433143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1144021473143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2580963 + ... + 2991556.
It is an arithmetic number, because the mean of its divisors is an integer number (286006802740).
Almost surely, 21144021433143 is an apocalyptic number.
1144021433143 is a deficient number, since it is larger than the sum of its proper divisors (5777817).
1144021433143 is an equidigital number, since it uses as much as digits as its factorization.
1144021433143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5777816.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1144021433143 its reverse (3413341204411), we get a palindrome (4557362637554).
The spelling of 1144021433143 in words is "one trillion, one hundred forty-four billion, twenty-one million, four hundred thirty-three thousand, one hundred forty-three".
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