114402213004003 has 4 divisors (see below), whose sum is σ = 114402238033968. Its totient is φ = 114402187974040.

The previous prime is 114402213003901. The next prime is 114402213004019. The reversal of 114402213004003 is 300400312204411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114402213004003 - 2²⁹ = 114401676133091 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114402213004903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3489343 + ... + 15523528.

It is an arithmetic number, because the mean of its divisors is an integer number (28600559508492).

Almost surely, 2^{114402213004003} is an apocalyptic number.

114402213004003 is a deficient number, since it is larger than the sum of its proper divisors (25029965).

114402213004003 is an equidigital number, since it uses as much as digits as its factorization.

114402213004003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25029964.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 114402213004003 its reverse (300400312204411), we get a palindrome (414802525208414).

The spelling of 114402213004003 in words is "one hundred fourteen trillion, four hundred two billion, two hundred thirteen million, four thousand, three".