Base | Representation |
---|---|
bin | 10101010100000111… |
… | …01100110100100011 |
3 | 1002112111002012222020 |
4 | 22222003230310203 |
5 | 141413404000311 |
6 | 5131251512523 |
7 | 553366106244 |
oct | 125203546443 |
9 | 32474065866 |
10 | 11443031331 |
11 | 4942324896 |
12 | 22742b8743 |
13 | 1104954474 |
14 | 7a7a76ccb |
15 | 46e902c06 |
hex | 2aa0ecd23 |
11443031331 has 4 divisors (see below), whose sum is σ = 15257375112. Its totient is φ = 7628687552.
The previous prime is 11443031321. The next prime is 11443031339. The reversal of 11443031331 is 13313034411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13313034411 = 3 ⋅4437678137.
It is a cyclic number.
It is not a de Polignac number, because 11443031331 - 26 = 11443031267 is a prime.
It is a super-2 number, since 2×114430313312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11443031339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1907171886 + ... + 1907171891.
It is an arithmetic number, because the mean of its divisors is an integer number (3814343778).
Almost surely, 211443031331 is an apocalyptic number.
11443031331 is a deficient number, since it is larger than the sum of its proper divisors (3814343781).
11443031331 is an equidigital number, since it uses as much as digits as its factorization.
11443031331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3814343780.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 11443031331 its reverse (13313034411), we get a palindrome (24756065742).
The spelling of 11443031331 in words is "eleven billion, four hundred forty-three million, thirty-one thousand, three hundred thirty-one".
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