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11443214131 = 172332888971
BaseRepresentation
bin10101010100001000…
…11001011100110011
31002112111102111201121
422222010121130303
5141413430323011
65131255443111
7553400500216
oct125204313463
932474374647
1011443214131
11494243a168
122274386497
1311049b972b
147a7ac377d
1546e93be71
hex2aa119733

11443214131 has 8 divisors (see below), whose sum is σ = 12168350064. Its totient is φ = 10723856640.

The previous prime is 11443214119. The next prime is 11443214141. The reversal of 11443214131 is 13141234411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11443214131 - 25 = 11443214099 is a prime.

It is a super-2 number, since 2×114432141312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11443214096 and 11443214105.

It is not an unprimeable number, because it can be changed into a prime (11443214141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1440525 + ... + 1448446.

It is an arithmetic number, because the mean of its divisors is an integer number (1521043758).

Almost surely, 211443214131 is an apocalyptic number.

11443214131 is a deficient number, since it is larger than the sum of its proper divisors (725135933).

11443214131 is a wasteful number, since it uses less digits than its factorization.

11443214131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2889221.

The product of its digits is 1152, while the sum is 25.

Adding to 11443214131 its reverse (13141234411), we get a palindrome (24584448542).

The spelling of 11443214131 in words is "eleven billion, four hundred forty-three million, two hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 17 233 3961 2888971 49112507 673130243 11443214131