Base | Representation |
---|---|
bin | 11010000001001110010101… |
… | …011001011000001110100001 |
3 | 120000011201101211111121011112 |
4 | 122001032111121120032201 |
5 | 104444333414423002340 |
6 | 1043213535211553105 |
7 | 33050351231025404 |
oct | 3201162531301641 |
9 | 500151354447145 |
10 | 114433320125345 |
11 | 33509997a38531 |
12 | 10a01b3b45b795 |
13 | 4bb10288aab10 |
14 | 20388607c5d3b |
15 | d36a1741b065 |
hex | 6813956583a1 |
114433320125345 has 32 divisors (see below), whose sum is σ = 151344371832192. Its totient is φ = 82527288947712.
The previous prime is 114433320125323. The next prime is 114433320125401. The reversal of 114433320125345 is 543521023334411.
It is a cyclic number.
It is not a de Polignac number, because 114433320125345 - 26 = 114433320125281 is a prime.
It is a super-2 number, since 2×1144333201253452 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16102322 + ... + 22094148.
It is an arithmetic number, because the mean of its divisors is an integer number (4729511619756).
Almost surely, 2114433320125345 is an apocalyptic number.
It is an amenable number.
114433320125345 is a deficient number, since it is larger than the sum of its proper divisors (36911051706847).
114433320125345 is a wasteful number, since it uses less digits than its factorization.
114433320125345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5998721.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 114433320125345 its reverse (543521023334411), we get a palindrome (657954343459756).
The spelling of 114433320125345 in words is "one hundred fourteen trillion, four hundred thirty-three billion, three hundred twenty million, one hundred twenty-five thousand, three hundred forty-five".
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