Base | Representation |
---|---|
bin | 10101010100001010… |
… | …01001110011101011 |
3 | 1002112111210120102121 |
4 | 22222011021303223 |
5 | 141414003142303 |
6 | 5131304012111 |
7 | 553402253536 |
oct | 125205116353 |
9 | 32474716377 |
10 | 11443412203 |
11 | 4942564a63 |
12 | 2274461037 |
13 | 1104a58932 |
14 | 7a7b35a1d |
15 | 46e97a9bd |
hex | 2aa149ceb |
11443412203 has 4 divisors (see below), whose sum is σ = 11940951888. Its totient is φ = 10945872520.
The previous prime is 11443412177. The next prime is 11443412213. The reversal of 11443412203 is 30221434411.
11443412203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11443412203 - 25 = 11443412171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11443412213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248769808 + ... + 248769853.
It is an arithmetic number, because the mean of its divisors is an integer number (2985237972).
Almost surely, 211443412203 is an apocalyptic number.
11443412203 is a deficient number, since it is larger than the sum of its proper divisors (497539685).
11443412203 is an equidigital number, since it uses as much as digits as its factorization.
11443412203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 497539684.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 11443412203 its reverse (30221434411), we get a palindrome (41664846614).
The spelling of 11443412203 in words is "eleven billion, four hundred forty-three million, four hundred twelve thousand, two hundred three".
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