Base | Representation |
---|---|
bin | 1101101001000… |
… | …10010000101001 |
3 | 21222022220110112 |
4 | 12310202100221 |
5 | 213243410423 |
6 | 15204424105 |
7 | 2556453032 |
oct | 664422051 |
9 | 258286415 |
10 | 114435113 |
11 | 59660881 |
12 | 323a8035 |
13 | 1a928cb0 |
14 | 112aba89 |
15 | a0a6a78 |
hex | 6d22429 |
114435113 has 4 divisors (see below), whose sum is σ = 123237828. Its totient is φ = 105632400.
The previous prime is 114435091. The next prime is 114435137. The reversal of 114435113 is 311534411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 19333609 + 95101504 = 4397^2 + 9752^2 .
It is a cyclic number.
It is not a de Polignac number, because 114435113 - 26 = 114435049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114431113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4401338 + ... + 4401363.
It is an arithmetic number, because the mean of its divisors is an integer number (30809457).
Almost surely, 2114435113 is an apocalyptic number.
114435113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
114435113 is a deficient number, since it is larger than the sum of its proper divisors (8802715).
114435113 is an equidigital number, since it uses as much as digits as its factorization.
114435113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8802714.
The product of its digits is 720, while the sum is 23.
The square root of 114435113 is about 10697.4348794466. The cubic root of 114435113 is about 485.4968699010.
Adding to 114435113 its reverse (311534411), we get a palindrome (425969524).
It can be divided in two parts, 114435 and 113, that multiplied together give a triangular number (12931155 = T5085).
The spelling of 114435113 in words is "one hundred fourteen million, four hundred thirty-five thousand, one hundred thirteen".
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