Base | Representation |
---|---|
bin | 1010011010001000010110… |
… | …0111010011100100011010 |
3 | 1111112001001102222222000001 |
4 | 2212202011213103210122 |
5 | 2444444340321100132 |
6 | 40201152241003214 |
7 | 2260542562450603 |
oct | 246420547234432 |
9 | 44461042888001 |
10 | 11444034550042 |
11 | 371242a181526 |
12 | 1349b2002350a |
13 | 650224942363 |
14 | 2b7c73a90daa |
15 | 14ca43d86ce7 |
hex | a68859d391a |
11444034550042 has 4 divisors (see below), whose sum is σ = 17166051825066. Its totient is φ = 5722017275020.
The previous prime is 11444034550033. The next prime is 11444034550057. The reversal of 11444034550042 is 24005543044411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11444019175801 + 15374241 = 3382901^2 + 3921^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11444034549983 and 11444034550010.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2861008637509 + ... + 2861008637512.
Almost surely, 211444034550042 is an apocalyptic number.
11444034550042 is a deficient number, since it is larger than the sum of its proper divisors (5722017275024).
11444034550042 is an equidigital number, since it uses as much as digits as its factorization.
11444034550042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5722017275023.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 11444034550042 its reverse (24005543044411), we get a palindrome (35449577594453).
The spelling of 11444034550042 in words is "eleven trillion, four hundred forty-four billion, thirty-four million, five hundred fifty thousand, forty-two".
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