114440632513 has 4 divisors (see below), whose sum is σ = 114441696000. Its totient is φ = 114439569028.

The previous prime is 114440632463. The next prime is 114440632541. The reversal of 114440632513 is 315236044411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 315236044411 = 10211 ⋅30872201.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114440632513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114440632013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 349513 + ... + 592486.

It is an arithmetic number, because the mean of its divisors is an integer number (28610424000).

Almost surely, 2^114440632513 is an apocalyptic number.

It is an amenable number.

114440632513 is a deficient number, since it is larger than the sum of its proper divisors (1063487).

114440632513 is an equidigital number, since it uses as much as digits as its factorization.

114440632513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1063486.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 114440632513 its reverse (315236044411), we get a palindrome (429676676924).

The spelling of 114440632513 in words is "one hundred fourteen billion, four hundred forty million, six hundred thirty-two thousand, five hundred thirteen".