114441021313 has 4 divisors (see below), whose sum is σ = 115453773828. Its totient is φ = 113428268800.

The previous prime is 114441021287. The next prime is 114441021329. The reversal of 114441021313 is 313120144411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 313120144411 = 29 ⋅10797246359.

It can be written as a sum of positive squares in 2 ways, for example, as 34197995329 + 80243025984 = 184927^2 + 283272^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114441021313 is a prime.

It is a super-3 number, since 3×114441021313³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114441021913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 506376088 + ... + 506376313.

It is an arithmetic number, because the mean of its divisors is an integer number (28863443457).

Almost surely, 2^114441021313 is an apocalyptic number.

It is an amenable number.

114441021313 is a deficient number, since it is larger than the sum of its proper divisors (1012752515).

114441021313 is a wasteful number, since it uses less digits than its factorization.

114441021313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1012752514.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 114441021313 its reverse (313120144411), we get a palindrome (427561165724).

The spelling of 114441021313 in words is "one hundred fourteen billion, four hundred forty-one million, twenty-one thousand, three hundred thirteen".