114441133012431 has 4 divisors (see below), whose sum is σ = 152588177349912. Its totient is φ = 76294088674952.

The previous prime is 114441133012351. The next prime is 114441133012433. The reversal of 114441133012431 is 134210331144411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114441133012431 - 2¹¹ = 114441133010383 is a prime.

It is a super-2 number, since 2×114441133012431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114441133012392 and 114441133012401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114441133012433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19073522168736 + ... + 19073522168741.

It is an arithmetic number, because the mean of its divisors is an integer number (38147044337478).

Almost surely, 2^{114441133012431} is an apocalyptic number.

114441133012431 is a deficient number, since it is larger than the sum of its proper divisors (38147044337481).

114441133012431 is an equidigital number, since it uses as much as digits as its factorization.

114441133012431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38147044337480.

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 114441133012431 its reverse (134210331144411), we get a palindrome (248651464156842).

The spelling of 114441133012431 in words is "one hundred fourteen trillion, four hundred forty-one billion, one hundred thirty-three million, twelve thousand, four hundred thirty-one".