114443014331215 has 4 divisors (see below), whose sum is σ = 137331617197464. Its totient is φ = 91554411464968.

The previous prime is 114443014331201. The next prime is 114443014331273. The reversal of 114443014331215 is 512133410344411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114443014331215 - 2¹⁵ = 114443014298447 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11444301433117 + ... + 11444301433126.

It is an arithmetic number, because the mean of its divisors is an integer number (34332904299366).

Almost surely, 2^{114443014331215} is an apocalyptic number.

114443014331215 is a deficient number, since it is larger than the sum of its proper divisors (22888602866249).

114443014331215 is an equidigital number, since it uses as much as digits as its factorization.

114443014331215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22888602866248.

The product of its (nonzero) digits is 69120, while the sum is 37.

Adding to 114443014331215 its reverse (512133410344411), we get a palindrome (626576424675626).

The spelling of 114443014331215 in words is "one hundred fourteen trillion, four hundred forty-three billion, fourteen million, three hundred thirty-one thousand, two hundred fifteen".