114505323123533 has 4 divisors (see below), whose sum is σ = 115329102426720. Its totient is φ = 113681543820348.

The previous prime is 114505323123517. The next prime is 114505323123577. The reversal of 114505323123533 is 335321323505411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114505323123533 - 2⁴ = 114505323123517 is a prime.

It is a super-2 number, since 2×114505323123533² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114505323123733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 411889651385 + ... + 411889651662.

It is an arithmetic number, because the mean of its divisors is an integer number (28832275606680).

Almost surely, 2^{114505323123533} is an apocalyptic number.

It is an amenable number.

114505323123533 is a deficient number, since it is larger than the sum of its proper divisors (823779303187).

114505323123533 is an equidigital number, since it uses as much as digits as its factorization.

114505323123533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 823779303186.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 114505323123533 its reverse (335321323505411), we get a palindrome (449826646628944).

The spelling of 114505323123533 in words is "one hundred fourteen trillion, five hundred five billion, three hundred twenty-three million, one hundred twenty-three thousand, five hundred thirty-three".