Base | Representation |
---|---|
bin | 1010011010100010110101… |
… | …1011111100111010010011 |
3 | 1111112201101222202222222101 |
4 | 2212220231123330322103 |
5 | 3000103421122110420 |
6 | 40204330005021231 |
7 | 2261214023315542 |
oct | 246505533747223 |
9 | 44481358688871 |
10 | 11451145113235 |
11 | 3715448981933 |
12 | 134b3853b4817 |
13 | 650ab8b19ab9 |
14 | 2b834a18c159 |
15 | 14cd0d24060a |
hex | a6a2d6fce93 |
11451145113235 has 64 divisors (see below), whose sum is σ = 14733569433600. Its totient is φ = 8518813535232.
The previous prime is 11451145113061. The next prime is 11451145113269. The reversal of 11451145113235 is 53231154115411.
It is a cyclic number.
It is not a de Polignac number, because 11451145113235 - 227 = 11451010895507 is a prime.
It is a super-2 number, since 2×114511451132352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11451145113194 and 11451145113203.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 962517807 + ... + 962529703.
It is an arithmetic number, because the mean of its divisors is an integer number (230212022400).
Almost surely, 211451145113235 is an apocalyptic number.
11451145113235 is a deficient number, since it is larger than the sum of its proper divisors (3282424320365).
11451145113235 is a wasteful number, since it uses less digits than its factorization.
11451145113235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12740.
The product of its digits is 36000, while the sum is 37.
Adding to 11451145113235 its reverse (53231154115411), we get a palindrome (64682299228646).
The spelling of 11451145113235 in words is "eleven trillion, four hundred fifty-one billion, one hundred forty-five million, one hundred thirteen thousand, two hundred thirty-five".
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