1145204314313 has 4 divisors (see below), whose sum is σ = 1155907158480. Its totient is φ = 1134501470148.

The previous prime is 1145204314307. The next prime is 1145204314333. The reversal of 1145204314313 is 3134134025411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1145204314313 - 2¹⁰ = 1145204313289 is a prime.

It is a super-2 number, since 2×1145204314313² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1145204314313.

It is not an unprimeable number, because it can be changed into a prime (1145204314333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5351421923 + ... + 5351422136.

It is an arithmetic number, because the mean of its divisors is an integer number (288976789620).

Almost surely, 2^{1145204314313} is an apocalyptic number.

It is an amenable number.

1145204314313 is a deficient number, since it is larger than the sum of its proper divisors (10702844167).

1145204314313 is a wasteful number, since it uses less digits than its factorization.

1145204314313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10702844166.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1145204314313 its reverse (3134134025411), we get a palindrome (4279338339724).

The spelling of 1145204314313 in words is "one trillion, one hundred forty-five billion, two hundred four million, three hundred fourteen thousand, three hundred thirteen".