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11454053141 = 22351363467
BaseRepresentation
bin10101010101011011…
…01111101100010101
31002120020211012001102
422222231233230111
5141424214200031
65132324035445
7553561562636
oct125255575425
932506735042
1011454053141
114948572723
122277b32b85
13110701314b
147a930588d
1547087d7cb
hex2aab6fb15

11454053141 has 4 divisors (see below), whose sum is σ = 11505416832. Its totient is φ = 11402689452.

The previous prime is 11454053129. The next prime is 11454053189. The reversal of 11454053141 is 14135045411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11454053141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11454053341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25681511 + ... + 25681956.

It is an arithmetic number, because the mean of its divisors is an integer number (2876354208).

Almost surely, 211454053141 is an apocalyptic number.

It is an amenable number.

11454053141 is a deficient number, since it is larger than the sum of its proper divisors (51363691).

11454053141 is an equidigital number, since it uses as much as digits as its factorization.

11454053141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51363690.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 11454053141 its reverse (14135045411), we get a palindrome (25589098552).

The spelling of 11454053141 in words is "eleven billion, four hundred fifty-four million, fifty-three thousand, one hundred forty-one".

Divisors: 1 223 51363467 11454053141