114544110142053 has 6 divisors (see below), whose sum is σ = 165452603538534. Its totient is φ = 76362740094696.

The previous prime is 114544110142031. The next prime is 114544110142061. The reversal of 114544110142053 is 350241011445411.

114544110142053 is a `hidden beast` number, since 1 + 1 + 4 + 5 + 441 + 1 + 0 + 1 + 4 + 205 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 59580599009409 + 54963511132644 = 7718847^2 + 7413738^2 .

It is not a de Polignac number, because 114544110142053 - 2⁹ = 114544110141541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114544110141999 and 114544110142017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114544110142093) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6363561674550 + ... + 6363561674567.

It is an arithmetic number, because the mean of its divisors is an integer number (27575433923089).

Almost surely, 2^{114544110142053} is an apocalyptic number.

It is an amenable number.

114544110142053 is a deficient number, since it is larger than the sum of its proper divisors (50908493396481).

114544110142053 is a wasteful number, since it uses less digits than its factorization.

114544110142053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12727123349123 (or 12727123349120 counting only the distinct ones).

The product of its (nonzero) digits is 38400, while the sum is 36.

Adding to 114544110142053 its reverse (350241011445411), we get a palindrome (464785121587464).

The spelling of 114544110142053 in words is "one hundred fourteen trillion, five hundred forty-four billion, one hundred ten million, one hundred forty-two thousand, fifty-three".