114555121244503 has 4 divisors (see below), whose sum is σ = 114604992871200. Its totient is φ = 114505249617808.

The previous prime is 114555121244461. The next prime is 114555121244521. The reversal of 114555121244503 is 305442121555411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114555121244503 - 2⁹ = 114555121243991 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114555121244503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114555121244303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24935809903 + ... + 24935814496.

It is an arithmetic number, because the mean of its divisors is an integer number (28651248217800).

Almost surely, 2^{114555121244503} is an apocalyptic number.

114555121244503 is a deficient number, since it is larger than the sum of its proper divisors (49871626697).

114555121244503 is an equidigital number, since it uses as much as digits as its factorization.

114555121244503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49871626696.

The product of its (nonzero) digits is 480000, while the sum is 43.

Adding to 114555121244503 its reverse (305442121555411), we get a palindrome (419997242799914).

The spelling of 114555121244503 in words is "one hundred fourteen trillion, five hundred fifty-five billion, one hundred twenty-one million, two hundred forty-four thousand, five hundred three".