Base | Representation |
---|---|
bin | 1010011011000101110100… |
… | …1001000011111001110111 |
3 | 1111120121122102021002122222 |
4 | 2212301131021003321313 |
5 | 3000232134030331403 |
6 | 40212521451312555 |
7 | 2261665515414164 |
oct | 246613511037167 |
9 | 44517572232588 |
10 | 11460535402103 |
11 | 3719427505947 |
12 | 135116614b75b |
13 | 6519543bb448 |
14 | 2b899b35b06b |
15 | 14d1ac813338 |
hex | a6c5d243e77 |
11460535402103 has 4 divisors (see below), whose sum is σ = 11571802736208. Its totient is φ = 11349268068000.
The previous prime is 11460535402093. The next prime is 11460535402139. The reversal of 11460535402103 is 30120453506411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11460535402103 - 24 = 11460535402087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11460535402153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55633666898 + ... + 55633667103.
It is an arithmetic number, because the mean of its divisors is an integer number (2892950684052).
Almost surely, 211460535402103 is an apocalyptic number.
11460535402103 is a deficient number, since it is larger than the sum of its proper divisors (111267334105).
11460535402103 is a wasteful number, since it uses less digits than its factorization.
11460535402103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111267334104.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 11460535402103 its reverse (30120453506411), we get a palindrome (41580988908514).
The spelling of 11460535402103 in words is "eleven trillion, four hundred sixty billion, five hundred thirty-five million, four hundred two thousand, one hundred three".
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