Base | Representation |
---|---|
bin | 110101011000100110… |
… | …1011001101101111111 |
3 | 101221220121120200221211 |
4 | 1222301031121231333 |
5 | 3334241402331033 |
6 | 124355500505251 |
7 | 11165640610060 |
oct | 1526115315577 |
9 | 357817520854 |
10 | 114642230143 |
11 | 4468a606351 |
12 | 1a27554b227 |
13 | aa701b1b4c |
14 | 5797954567 |
15 | 2eae92d2cd |
hex | 1ab1359b7f |
114642230143 has 4 divisors (see below), whose sum is σ = 131019691600. Its totient is φ = 98264768688.
The previous prime is 114642230137. The next prime is 114642230201. The reversal of 114642230143 is 341032246411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114642230143 - 217 = 114642099071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114642240143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8188730718 + ... + 8188730731.
It is an arithmetic number, because the mean of its divisors is an integer number (32754922900).
Almost surely, 2114642230143 is an apocalyptic number.
114642230143 is a deficient number, since it is larger than the sum of its proper divisors (16377461457).
114642230143 is an equidigital number, since it uses as much as digits as its factorization.
114642230143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16377461456.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 114642230143 its reverse (341032246411), we get a palindrome (455674476554).
The spelling of 114642230143 in words is "one hundred fourteen billion, six hundred forty-two million, two hundred thirty thousand, one hundred forty-three".
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