Search a number
-
+
114642230143 = 716377461449
BaseRepresentation
bin110101011000100110…
…1011001101101111111
3101221220121120200221211
41222301031121231333
53334241402331033
6124355500505251
711165640610060
oct1526115315577
9357817520854
10114642230143
114468a606351
121a27554b227
13aa701b1b4c
145797954567
152eae92d2cd
hex1ab1359b7f

114642230143 has 4 divisors (see below), whose sum is σ = 131019691600. Its totient is φ = 98264768688.

The previous prime is 114642230137. The next prime is 114642230201. The reversal of 114642230143 is 341032246411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114642230143 - 217 = 114642099071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114642240143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8188730718 + ... + 8188730731.

It is an arithmetic number, because the mean of its divisors is an integer number (32754922900).

Almost surely, 2114642230143 is an apocalyptic number.

114642230143 is a deficient number, since it is larger than the sum of its proper divisors (16377461457).

114642230143 is an equidigital number, since it uses as much as digits as its factorization.

114642230143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16377461456.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 114642230143 its reverse (341032246411), we get a palindrome (455674476554).

The spelling of 114642230143 in words is "one hundred fourteen billion, six hundred forty-two million, two hundred thirty thousand, one hundred forty-three".

Divisors: 1 7 16377461449 114642230143