114710341153 has 4 divisors (see below), whose sum is σ = 115050728260. Its totient is φ = 114369954048.

The previous prime is 114710341147. The next prime is 114710341157. The reversal of 114710341153 is 351143017411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 351143017411 = 484229 ⋅725159.

It can be written as a sum of positive squares in 2 ways, for example, as 17358853009 + 97351488144 = 131753^2 + 312012^2 .

It is a cyclic number.

It is not a de Polignac number, because 114710341153 - 2⁵ = 114710341121 is a prime.

It is a super-4 number, since 4×114710341153⁴ (a number of 45 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114710341157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170193048 + ... + 170193721.

It is an arithmetic number, because the mean of its divisors is an integer number (28762682065).

Almost surely, 2^114710341153 is an apocalyptic number.

It is an amenable number.

114710341153 is a deficient number, since it is larger than the sum of its proper divisors (340387107).

114710341153 is an equidigital number, since it uses as much as digits as its factorization.

114710341153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 340387106.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 114710341153 its reverse (351143017411), we get a palindrome (465853358564).

The spelling of 114710341153 in words is "one hundred fourteen billion, seven hundred ten million, three hundred forty-one thousand, one hundred fifty-three".