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11475434110415 = 5112027102932539
BaseRepresentation
bin1010011011111101010100…
…1011000111110111001111
31111122001002201210220021112
42212333111023013313033
53001003142113013130
640223424110322235
72263033645351442
oct246772513076717
944561081726245
1011475434110415
113724782433a20
1213540237b937b
13653189c60a92
142b95b1d35659
1514d7807ba495
hexa6fd52c7dcf

11475434110415 has 16 divisors (see below), whose sum is σ = 15029797760640. Its totient is φ = 8341652879520.

The previous prime is 11475434110333. The next prime is 11475434110423. The reversal of 11475434110415 is 51401143457411.

It is not a de Polignac number, because 11475434110415 - 220 = 11475433061839 is a prime.

It is a super-2 number, since 2×114754341104152 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51354785 + ... + 51577754.

It is an arithmetic number, because the mean of its divisors is an integer number (939362360040).

Almost surely, 211475434110415 is an apocalyptic number.

11475434110415 is a deficient number, since it is larger than the sum of its proper divisors (3554363650225).

11475434110415 is a wasteful number, since it uses less digits than its factorization.

11475434110415 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102934582.

The product of its (nonzero) digits is 134400, while the sum is 41.

Adding to 11475434110415 its reverse (51401143457411), we get a palindrome (62876577567826).

The spelling of 11475434110415 in words is "eleven trillion, four hundred seventy-five billion, four hundred thirty-four million, one hundred ten thousand, four hundred fifteen".

Divisors: 1 5 11 55 2027 10135 22297 111485 102932539 514662695 1132257929 5661289645 208644256553 1043221282765 2295086822083 11475434110415