114930135 has 12 divisors (see below), whose sum is σ = 199212312. Its totient is φ = 61296048.

The previous prime is 114930131. The next prime is 114930163. The reversal of 114930135 is 531039411.

It is not a de Polignac number, because 114930135 - 2² = 114930131 is a prime.

It is a super-2 number, since 2×114930135² = 26417871862236450, which contains 22 as substring.

It is a hoax number, since the sum of its digits (27) coincides with the sum of the digits of its distinct prime factors.

It is a junction number, because it is equal to n+sod(n) for n = 114930099 and 114930108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114930131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1276957 + ... + 1277046.

It is an arithmetic number, because the mean of its divisors is an integer number (16601026).

Almost surely, 2^114930135 is an apocalyptic number.

114930135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

114930135 is a deficient number, since it is larger than the sum of its proper divisors (84282177).

114930135 is a wasteful number, since it uses less digits than its factorization.

114930135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2554014 (or 2554011 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 27.

The square root of 114930135 is about 10720.5473274456. The cubic root of 114930135 is about 486.1959150176.

Adding to 114930135 its reverse (531039411), we get a palindrome (645969546).

The spelling of 114930135 in words is "one hundred fourteen million, nine hundred thirty thousand, one hundred thirty-five".