Base | Representation |
---|---|
bin | 11010001001011111001001… |
… | …001010111111111100000001 |
3 | 120002012000000002112002122002 |
4 | 122021133021022333330001 |
5 | 110033134300330013040 |
6 | 1044330442013153345 |
7 | 33136362033134666 |
oct | 3211371112777401 |
9 | 502160002462562 |
10 | 115001124454145 |
11 | 337087807547a6 |
12 | 10a93ba3a8b855 |
13 | 4c227372c8cb7 |
14 | 2058126b8da6d |
15 | d4669a9eaa15 |
hex | 6897c92bff01 |
115001124454145 has 16 divisors (see below), whose sum is σ = 139664546844480. Its totient is φ = 90892109653824.
The previous prime is 115001124454133. The next prime is 115001124454147. The reversal of 115001124454145 is 541454421100511.
It is a cyclic number.
It is not a de Polignac number, because 115001124454145 - 212 = 115001124450049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115001124454099 and 115001124454108.
It is not an unprimeable number, because it can be changed into a prime (115001124454147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216579386 + ... + 217109724.
It is an arithmetic number, because the mean of its divisors is an integer number (8729034177780).
Almost surely, 2115001124454145 is an apocalyptic number.
It is an amenable number.
115001124454145 is a deficient number, since it is larger than the sum of its proper divisors (24663422390335).
115001124454145 is an equidigital number, since it uses as much as digits as its factorization.
115001124454145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1052944.
The product of its (nonzero) digits is 64000, while the sum is 38.
Adding to 115001124454145 its reverse (541454421100511), we get a palindrome (656455545554656).
The spelling of 115001124454145 in words is "one hundred fifteen trillion, one billion, one hundred twenty-four million, four hundred fifty-four thousand, one hundred forty-five".
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