115001200024133 has 4 divisors (see below), whose sum is σ = 116075977594560. Its totient is φ = 113926422453708.

The previous prime is 115001200024069. The next prime is 115001200024157. The reversal of 115001200024133 is 331420002100511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115001200024133 - 2⁶ = 115001200024069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115001200024099 and 115001200024108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115001200024163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 537388785053 + ... + 537388785266.

It is an arithmetic number, because the mean of its divisors is an integer number (29018994398640).

Almost surely, 2^{115001200024133} is an apocalyptic number.

It is an amenable number.

115001200024133 is a deficient number, since it is larger than the sum of its proper divisors (1074777570427).

115001200024133 is a wasteful number, since it uses less digits than its factorization.

115001200024133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1074777570426.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 115001200024133 its reverse (331420002100511), we get a palindrome (446421202124644).

The spelling of 115001200024133 in words is "one hundred fifteen trillion, one billion, two hundred million, twenty-four thousand, one hundred thirty-three".