115001202123131 has 4 divisors (see below), whose sum is σ = 115001227646064. Its totient is φ = 115001176600200.

The previous prime is 115001202123053. The next prime is 115001202123149. The reversal of 115001202123131 is 131321202100511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115001202123131 is a prime.

It is a super-4 number, since 4×115001202123131⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115001202123097 and 115001202123106.

It is not an unprimeable number, because it can be changed into a prime (115001202123931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3995735 + ... + 15683376.

It is an arithmetic number, because the mean of its divisors is an integer number (28750306911516).

Almost surely, 2^{115001202123131} is an apocalyptic number.

115001202123131 is a deficient number, since it is larger than the sum of its proper divisors (25522933).

115001202123131 is an equidigital number, since it uses as much as digits as its factorization.

115001202123131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25522932.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 115001202123131 its reverse (131321202100511), we get a palindrome (246322404223642).

The spelling of 115001202123131 in words is "one hundred fifteen trillion, one billion, two hundred two million, one hundred twenty-three thousand, one hundred thirty-one".