Base | Representation |
---|---|
bin | 11010001001011111001101… |
… | …110011010010000110001101 |
3 | 120002012000012111200002110212 |
4 | 122021133031303102012031 |
5 | 110033134430220420044 |
6 | 1044330453430012205 |
7 | 33136363665252146 |
oct | 3211371563220615 |
9 | 502160174602425 |
10 | 115001202123149 |
11 | 33708810583661 |
12 | 10a94005aa7065 |
13 | 4c2274a4213a4 |
14 | 205813320aacd |
15 | d466a273da9e |
hex | 6897cdcd218d |
115001202123149 has 2 divisors, whose sum is σ = 115001202123150. Its totient is φ = 115001202123148.
The previous prime is 115001202123053. The next prime is 115001202123167. The reversal of 115001202123149 is 941321202100511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87956074680100 + 27045127443049 = 9378490^2 + 5200493^2 .
It is a cyclic number.
It is not a de Polignac number, because 115001202123149 - 216 = 115001202057613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115001202120149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57500601061574 + 57500601061575.
It is an arithmetic number, because the mean of its divisors is an integer number (57500601061575).
Almost surely, 2115001202123149 is an apocalyptic number.
It is an amenable number.
115001202123149 is a deficient number, since it is larger than the sum of its proper divisors (1).
115001202123149 is an equidigital number, since it uses as much as digits as its factorization.
115001202123149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 115001202123149 in words is "one hundred fifteen trillion, one billion, two hundred two million, one hundred twenty-three thousand, one hundred forty-nine".
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