1150101341 has 4 divisors (see below), whose sum is σ = 1150169184. Its totient is φ = 1150033500.

The previous prime is 1150101317. The next prime is 1150101347. The reversal of 1150101341 is 1431010511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1431010511 = 7 ⋅204430073.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1150101341 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150101347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15866 + ... + 50516.

It is an arithmetic number, because the mean of its divisors is an integer number (287542296).

Almost surely, 2^1150101341 is an apocalyptic number.

It is an amenable number.

1150101341 is a deficient number, since it is larger than the sum of its proper divisors (67843).

1150101341 is an equidigital number, since it uses as much as digits as its factorization.

1150101341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67842.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1150101341 is about 33913.1440742376. The cubic root of 1150101341 is about 1047.7203273132.

Adding to 1150101341 its reverse (1431010511), we get a palindrome (2581111852).

The spelling of 1150101341 in words is "one billion, one hundred fifty million, one hundred one thousand, three hundred forty-one".