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1150145234551 = 1975838300683
BaseRepresentation
bin10000101111001001111…
…111111000011001110111
311001221201121011121201001
4100233021333320121313
5122320444140001201
62240211443544131
7146044446121435
oct20571177703167
94057647147631
101150145234551
114038570009a5
12166aa538b047
13845c5968ab1
143d94b201d55
151edb7e83301
hex10bc9ff8677

1150145234551 has 4 divisors (see below), whose sum is σ = 1155983535432. Its totient is φ = 1144306933672.

The previous prime is 1150145234533. The next prime is 1150145234597. The reversal of 1150145234551 is 1554325410511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1150145234551 - 25 = 1150145234519 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1150145234551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150145234501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2919150145 + ... + 2919150538.

It is an arithmetic number, because the mean of its divisors is an integer number (288995883858).

Almost surely, 21150145234551 is an apocalyptic number.

1150145234551 is a deficient number, since it is larger than the sum of its proper divisors (5838300881).

1150145234551 is an equidigital number, since it uses as much as digits as its factorization.

1150145234551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5838300880.

The product of its (nonzero) digits is 60000, while the sum is 37.

The spelling of 1150145234551 in words is "one trillion, one hundred fifty billion, one hundred forty-five million, two hundred thirty-four thousand, five hundred fifty-one".

Divisors: 1 197 5838300683 1150145234551