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1150220103 = 3383406701
BaseRepresentation
bin100010010001110…
…1111011101000111
32222011100020100120
41010203233131013
54323424020403
6310045113023
740334465244
oct10443573507
92864306316
101150220103
115402a642a
12281258773
131543b5316
14aca925cb
156aea5e53
hex448ef747

1150220103 has 4 divisors (see below), whose sum is σ = 1533626808. Its totient is φ = 766813400.

The previous prime is 1150220053. The next prime is 1150220129. The reversal of 1150220103 is 3010220511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1150220103 - 210 = 1150219079 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150220003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191703348 + ... + 191703353.

It is an arithmetic number, because the mean of its divisors is an integer number (383406702).

Almost surely, 21150220103 is an apocalyptic number.

1150220103 is a deficient number, since it is larger than the sum of its proper divisors (383406705).

1150220103 is an equidigital number, since it uses as much as digits as its factorization.

1150220103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383406704.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 1150220103 is about 33914.8950020489. The cubic root of 1150220103 is about 1047.7563893756.

Adding to 1150220103 its reverse (3010220511), we get a palindrome (4160440614).

The spelling of 1150220103 in words is "one billion, one hundred fifty million, two hundred twenty thousand, one hundred three".

Divisors: 1 3 383406701 1150220103